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0=-4.9x^2+8x+3
We move all terms to the left:
0-(-4.9x^2+8x+3)=0
We add all the numbers together, and all the variables
-(-4.9x^2+8x+3)=0
We get rid of parentheses
4.9x^2-8x-3=0
a = 4.9; b = -8; c = -3;
Δ = b2-4ac
Δ = -82-4·4.9·(-3)
Δ = 122.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{122.8}}{2*4.9}=\frac{8-\sqrt{122.8}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{122.8}}{2*4.9}=\frac{8+\sqrt{122.8}}{9.8} $
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